Sorry - I'm looking to have 6 groups, no fewer.
I'd like the groups scored by how many items they contain different from the ideal (the lower, the better):
my $ideal_avg_per_group = @list / 6;
# your solution
my $solution = [
[1 1 1 2 3],
[4 4 4 5 5],
[6 6 6 7 7],
[8 8 8]
];
my $this_score = 0;
for (@$solution) {
my $num_items = @$_;
$this_score += abs($ideal_avg_per_group - $num_items);
}
Also, it's fine to assume that there are more than 6 unique values in the list. Otherwise, it's obviously very easy.
Thanks!
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