Hi,
I have problem of filtering a log file from my perl script.
This is the file content of the file pinpe.csv:
2009-06-16
2009-01-29
2009-06-02
2008-03-05
2007-08-05
Here is my perl code.
use Net::Telnet;
@DATE=$telnet->cmd("date '+%Y-%m-%d'");
chomp($DATE[0]);
@Discon=$telnet->cmd("cat /data/pinpe.csv | nawk '{print \$4}' | perl
+-ne 'print if \$_ lt $DATE[0]'");
chomp($Discon[0]);
print "@Discon[0]\n";
and this is the output error:
Illegal octal digit '8' at -e line 1, at end of line
Now my dilemma is I want to filter this ouput by my preferred dates. I wanted it to output the date from yesterday and backwards. In other words I want to filter all the dates less than today's date (i.e. 2007-07-30, 2007-07-29, 2007-07-28, etc. and below).
Tnx in advance. :)
Was it perl thought that I was dealing with an octal number and when he came along with 8 which stopped it from making any sense, so perl quite rightly complained? Pls help. Tnx.
Br,
Pete
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