Just taking the first of those problem lines should make it clear to you:
print ((128&$bin)/128);
This takes your number in $bin and bitwise-ANDs it with 128 (27 = 128). The result of that will be either 128 or 0. Divide that result by 128 and you get zero or one.
Repeat for 64 (26) down to 1 (20) and you have your binary number.
Take 123, for example
| 123 | & | 128 | = | 0 | / | 128 | = | 0 |
| 123 | & | 64 | = | 64 | / | 64 | = | 1 |
| 123 | & | 32 | = | 32 | / | 32 | = | 1 |
| 123 | & | 16 | = | 16 | / | 16 | = | 1 |
| 123 | & | 8 | = | 8 | / | 8 | = | 1 |
| 123 | & | 4 | = | 0 | / | 4 | = | 0 |
| 123 | & | 2 | = | 2 | / | 2 | = | 1 |
| 123 | & | 1 | = | 1 | / | 1 | = | 1 |
Read the binary, top to bottom: 123
10 = 01111011
2
update: added the example
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