I appreciate that you are trying, but you are still not making any sense. You are not using "code" tags enough in your posts, you are not giving us anything we can try to run ourselves to demonstrate your problem, and you keep confusing "slash" with "\".

I'll propose the following, which is based on code and data in the original post at the top of this thread. Please try this out, tell us whether it works for you, and if it doesn't (and you are still stumped about how to make it work), tell us exactly how it should work.

#!/usr/bin/perl

use strict;
use warnings;

while (<DATA>) {
    print "$1\n" if ( m{^\*\s+(?:/\w+)+\s+(.+?)\s+} );
}

__DATA__
* /vobs/bt_rel /usr/add-on/puccase_vob01/ccvob01/bt_rel.vbs public (re
+plicated)
* /scm /usr/add-on/puccase_vob01/ccvob01/scm.vbs public (replicated)
* /v_dialermidtier /usr/addon/puccase_vob01/ccvob01/v_dialermidtier.vb
+s public (replicated)
* /v_dialer /usr/add-on/puccase_vob01/ccvob01/v_dialer.vbs public (rep
+licated)
* /vobs/UMTools /user/addon/puccase_vob01/ccvob01/UMtools.vbs replicat
+ed)
[download]

The difference between that and the OP code is:

• it loops over each line of input, instead of reporting only a single output from all lines of input
• it escapes the initial "*" character in the regex, to avoid a syntax error
• it puts curlies around the regex, to avoid \/ (toothpick syndrome)
• it allows the first string following "*" to contain any number (1 or more) of adjacent "/word" patterns (but does not capture this string)

If you are just trying to get the third space-delimited token from each line of input, you could do this for each line, instead of the regex match:

     print +(split /\s+/)[2];  # print third "word" of line
[download]

(updated to include "+" outside the parens -- thanks, naikonta!)

If the data shown above is not correct, show us the actual data (inside <code> tags, please). If the output is not what you want, show us exactly what you want (based on the correct input data, again using <code> tags).

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