In fact your previous solution was O(N log N) for N = $pad*@nums because of the sort, not O(Nē) (or did I miss something)?

However your current solution stores some amount of data twice in a hash where pointer is sufficient because @nums is already sorted.

Perl 6 in German

In reply to Re^2: Padding search results with context by moritz
in thread Padding search results with context by moritz

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