It's sometimes easier to just join the numbers form 1 to 300000 and take the first 10^6 digits of that.

It also helps to have a repl-loop so you can quickly try out how long the concatenation of 1..300000 takes and correct the number to a better approximation in a few steps.

(... types some quick lines to an interpreter ... things like # ; <@":"0 i.3e5 and 01234567891011121314151617181920212223242526272829303132333435363738394041424344 flicker on the screen ... yep, 1..2e5 is enough)

Yeah, I'm not a lazy languages guy. Quite the opposite. Especially for quick calculations like this. How did you guess?

In reply to Re: [perl 6] re reduction operators by ambrus
in thread [perl 6] re reduction operators by blazar

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