Hmmm...I tried to get my head around references and hard references. I thought a hard reference has the \ in front of it. I was passing the hash, as I posted just a minute ago, with the \ infront of it.

Can you explain the difference between "my %subhash" and "my (%subhash)" in your examples? I would have never in a million years (well, maybe) gotten to the point where I would tried parenthesis around a variable. They look optional to me.

Regardless, I took off the \ where I passed the hash to the function...and it worked. I'm very relieved at the moment, but have no understanding about why this works, which is troubling after trying so hard to understand this.

Thanks again!

Doug

In reply to Re^2: Trouble passing hash into function by dbonneville
in thread Trouble passing hash into function by dbonneville

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