Ruby solution 
x = []
"ZBBBCZZ".scan(/((.)\2*)/){ x << [$~[0]]; x.flatten!}

[download]
.flatten is needed else you get 
# => [["Z"], ["BBB"], ["C"], ["ZZ"]]

[download]
as result.

But this is quite an ugly solution anyway... in fact, perl looks almost as readable in this example ;)

not sure how to solve this any easier though, hmm i wonder if .each could be used and then another grouping way... I really dont like the regex magic of the ruby solution, cant you guys think of another solution :-)

In reply to Re^2: Yet Another Rosetta Code Problem (Perl, Ruby, Python, Haskell, ...) by Anonymous Monk
in thread Yet Another Rosetta Code Problem (Perl, Ruby, Python, Haskell, ...) by eyepopslikeamosquito

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