Maybe something like this?

echo stuff | perl -ne '$x=shift; print "x=$x\n"' - myarg

It's always a good idea to tell what the expected outcome is :)

With one line of input on stdin (like your echo), this produces the same result as bart's suggestion. With more lines on stdin, however, you'd get different behaviour. Assuming that stuff is a file containing the two lines "foo" and "bar", then when doing

cat stuff | perl -ne '$x=shift; print "x=$x\n"; print "<>=$_"' - myarg + myarg2 stuff

you'd get

x=myarg <>=foo x=myarg2 <>=bar x= <>=foo x= <>=bar

i.e. you'd shift as many arguments from @ARGV as there are lines on stdin. For the remaining arguments, Perl would try to open the respective filename.


In reply to Re: Differentiating STDIN from arguments when using -n ? by almut
in thread Differentiating STDIN from arguments when using -n ? by rduke15

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