Just to make something clear, by trying to assess context in your tied hash, you are breaking a Perl idiom: that hash values are only ever scalars. That scalar may be a reference to something else, like an array or hash, but the hash value itself is only ever a scalar.
Consider this:
%fs = (
dir1 => [ 'file1','file2','file3' ],
dir2 => [ 'file4','file5','file6' ],
);
$contents = $fs{dir1};
$file = $fd{dir1}[0];
I would expect $contents to contain an array-ref, and $file to contain a scalar string. If I wanted an array returned instead, I would write:
@contents = @{$fs{dir1}};
which would still work with your code, because the
@ converts the reference to a list, OUTSIDE the tied class. To do otherwise would, in my opinion, just add confusion:
this works just like a hash, except when it doesn't...
Clint
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