open (OUTHANDLE, ">$basedir . /output/file.txt") or die ;
You're trying to open a file that doesn't exist. 
perl -le 'print ">$basedir . /output/file.txt"'
results . /output/file.txt

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There's no concatenating operator there, you clobber them all in one single string, the $basedir, the dot with spaces ( .), and /output/file.txt. Should you use $! variable, Perl would tell you what was wrong. 
my $basedir = "results";
my $filename = "$basedir . /output/file.txt";
open (OUTHANDLE, ">$filename") or die "can't open ($filename): $!\n";
can't open (result . /output/file.txt): No such file or directory

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You actually want, 
open (OUTHANDLE, ">$basedir" . "/output/file.txt") or die $!;

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but this is not good although it probably works. Use suggestions from other replies.

Open source softwares? Share and enjoy. Make profit from them if you can. Yet, share and enjoy!

In reply to Re: opening files where name is a concatenation of variable by naikonta
in thread opening files where name is a concatenation of variable by confused_newbie

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