Folks, Please refer :
http://www.perlmonks.org/index.pl?node_id=643792

The fact is that I am totally lost now :-)
My objective was/is: To read a flat file which has SAR (system activity reporter) data and then to generate the graph using that data. I have module for graph but the problem here is the data needs to be transversed (row-> columns). My data looks like: 
17:12:41       0       0       0     100
17:12:42       0       1       0      99
17:12:43       0       0       0     100
:
:

[download]
And for the graph creation, I need this data in following format: 
17:12:41    17:12:42    17:12:43  :     :    ...  ...  ...
0           0           0         :     :    ...  ...  ...
0           1           0         :     :    ...  ...  ...
0           0           0         :     :    ...  ...  ...
100         99          100       :     :    ...  ...  ...

[download]
Finally, to get an array like below: 
my @data = (
['17:12:41','17:12:42','17:12:43'.........],
['0','1','0'.........],
['0','0','0'.........],
['100','99','100'.....]);

[download]
Being a Unix admin, I can do this thing by a shell script, but for graphs, I will have to again come back to perl... thats why I am looking for perl solution so that it can be done in one perl script itself. Hope I asked the question right this time. :-)

Once I get this solution, I will integrate it with the performance monitoring graphs and share in this thread.

In reply to How to swap rows with columns? - Still unresolved :( by perl_geek

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