Be careful when you omit parens. You got lucky because of eval's prototype, but other functions aren't as forgiving.

eval $var1 || eval $var2;
means
eval($var1) || eval($var2);

For non-exceptional functions,
func $var1 || func $var2;
means
func($var1 || func($var2));

In reply to Re: When is 'eval' too inefficient? by ikegami
in thread When is 'eval' too inefficient? by argv

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