One thing I did notice in your code (and after runnning) was that the word count seems to be just 1.

Sorry,
my $word_count = () = split(' ', $file);
should be
my $word_count = split(' ', $file);

I now have another problem in that some terms are still not picked up

\b matches between \w\W, \W\w, ^\w and \w\z. As such, the second \b won't match in 'h(2)O(2) water' =~ '/\b\Qh(2)O(2)\Q\b/. () is a \W, and so is the following space.) Perhaps this will do the trick:

/(?:\W|^)\Q$term\E(?:(?=\W)|\z)/

[download]

I think the following would be faster, but it would count a repeated term as one:

/(?:\W|^)\Q$term\E(?:\W|\z)/

[download]

If you want the match to be case-insensitive, one solution is to use the i modifier on your match.

In reply to Re^3: Regex word boundries by ikegami
in thread Regex word boundries by MonkPaul

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