/o tells the compiler that the variables mentioned in the regex won't change while the program is running, so it only needs to be compiled once. If your regex contains no variables, then /o doesn't do anything.
| We're not surrounded, we're in a target-rich environment! |
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In reply to Re^2: Why this code run faster?
by jasonk
in thread Why this code run faster?
by Gangabass
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