You are incorrect. /o is only operative when there is interpolation in the pattern. Since there is none - the pattern is compiled only once and at that is at the normal perl compile-time. That is, right along at the same time as the surrounding code. Compilation of interpolated patterns is deferred to runtime. If /o were present then the first interpolated pattern would be baked in.

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In reply to Re^2: Why this code run faster? by diotalevi
in thread Why this code run faster? by Gangabass

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