Hi

Sorry I misunderstood your question on my previous post.

From perldoc system:

This is not what you want to use to capture the output from a command, for that you should use merely backticks or qx//, as described in "`STRING`" in perlop.

To read both a command's STDOUT and its STDERR separately, it's easiest to redirect them separately to files, and then read from those files when the program is done: 

system("program args 1>program.stdout 2>program.stderr");

Original submission:

Hi

The following code doesn't print anything on the screen: 

`echo test`;
The following, instead, does: 
print `echo test`;

The backticks (man perlop) just spawn a new process, execute the stuff, and capture the output on the left-hand-side variable.

Example: 

my $output = `echo 123!`;
print $output

Basically, what has happened to your code is that the string got echoed on _another_ process, whose output you never bothered printing.

Hope this helps

In reply to Re: Problem with backtick? by okram
in thread Problem with backtick? by iPerl

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