sub func1(\@)
{
  my $arg1 = shift;
  @arr=@{$arg1};
  $,="#";
  print @arr;
  func2(@arr);
}

sub func2(\@)
{
  my $arg1=shift;
  my @numbers= @{$arg1};
  $,="-";
  print @numbers; #not printed at all (?)
  print "\n";
  print $arg1->[0];
  print $arg1; #prints 10 (?), it should have been a reference
  print "\n";
}

$,=" ";
@arr=(10,400,2,7,20,40,23,100,2);
print "original Array is ", @arr,"\n";
func1(@arr);
print "\n";

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In reply to Can you explain me the output of this programme. especially in the subroutine func2 by sanketkathalkar

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