Hey monks!
I was coding a little program in C and i got stuck on something.
#include <stdio.h>
int main() {
char answer=' ';
printf("(F)irst,(S)econd,(T)hird\n");
scanf("%c",&answer);
while(answer !='F' && answer !='S' && answer !='T') {
printf("(F)irst,(S)econd,(T)hird\n");
scanf("%c",&answer);
}
return 0;
}
If I enter something different than F,S or T , I get the message "(F)irst,(S)econd,(T)hird" printed more than it should.
I ran the code in gdb and the scanf line is skipped once before it's executed.In perl ,the code :
my $ans;
print "(F)irst,(S)econd,(T)hird\n";
chomp($ans=<STDIN>);
while($ans ne 'F' && $ans ne 'S' && $ans ne 'T') {
print "(F)irst,(S)econd,(T)hird\n";
chomp($ans=<STDIN>);
}
runs just fine .
I'm guessing it's something about buffering , but I'm not sure.
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