Hey monks!
I was coding a little program in C and i got stuck on something.
#include <stdio.h> int main() { char answer=' '; printf("(F)irst,(S)econd,(T)hird\n"); scanf("%c",&answer); while(answer !='F' && answer !='S' && answer !='T') { printf("(F)irst,(S)econd,(T)hird\n"); scanf("%c",&answer); } return 0; }
If I enter something different than F,S or T , I get the message "(F)irst,(S)econd,(T)hird" printed more than it should.
I ran the code in gdb and the scanf line is skipped once before it's executed.In perl ,the code :
my $ans; print "(F)irst,(S)econd,(T)hird\n"; chomp($ans=<STDIN>); while($ans ne 'F' && $ans ne 'S' && $ans ne 'T') { print "(F)irst,(S)econd,(T)hird\n"; chomp($ans=<STDIN>); }
runs just fine .
I'm guessing it's something about buffering , but I'm not sure.

In reply to Why does perl get this right and C doesn't ? by Alien

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