This results in an error, because the string $b has a regex metacharacter, $, in it. Here's the alternative I've come up with so far:my $a = "$"; my $b = "$"; my $c = "x"; $a =~ s/$b/$c/g; print "a=$a\n";
Is there a simpler way to do this? I'm thinking of making this into a module, because I have several different programs that use it, but it seems like there must be an easier way to do such a common task. TIA!# conceptually, the following is like $a=~s/$b/$c/, but is safe if $b +has metacharacters in it sub string_substitution_one { my $a_ref = shift; my $b = shift; my $c = shift; my $a = $$a_ref; my $debug = ($b eq '$m$'); my $i=index($a,$b); return 0 if $i == -1; my $z = ''; if ($i>0) {$z = $z . substr($a,0,$i)} $z = $z . $c; if ($i+length($b)<length($a)) {$z = $z . substr($a,$i+length($b),len +gth($a)-($i+length($b)))} $$a_ref = $z; return 1; } # conceptually, the following is like $a=~s/$b/$c/g, but is safe if $b + has metacharacters in it sub string_substitution_global { my $a_ref = shift; my $b = shift; my $c = shift; my $found = 0; while (string_substitution_one($a_ref,$b,$c)) { $found = 1; } return $found; }
In reply to s/$foo/$bar/ when $foo has metacharacters in it by bcrowell2
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