Good work. 
# This line would discard the reference to %Fruits, and create a *new*
# hash with the specified values
# $Ref_to_Hash = { "Pears", 5, "Peaches", 7 };

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The solution is to not change the reference, but the dereferenced hash: 
%$Ref_to_Hash = ( "Pears", 5, "Peaches", 7 );

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In reply to Re^2: Modify a hash via its reference by bart
in thread Modify a hash via its reference by Philippe

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