This is the part which is responsible for giving me the result, but i have a small problem with this, this jus gives me the number which is present after the search phrase not the number before that.

The perl program actually searches for a pattern and returns a number present after the pattern in the log file.

My search phrase will be something like:

total rows rejected:
or
rows rejected

For example,

total rows rejected: 4000

it is able to give the value 4000 as the result

but if my search phrase is

3000 rows rejected

its not able to give 3000

could somebody help in this?
print qq{$1\n} if ($lines[ $lineNo ] =~ m{\Q$Phrase\E\s*(\d*)});
thanks.
Note: johngg helped me in writing this code... credit goes to him.

In reply to search pattern with digits by mercuryshipz

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