I think your "uninitialized value" warning is explained in Use of uninitialized value in open second time but not first. The fix is to initialize $out when it's created. 

my $out = '';

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(I tried this, and it worked for me.)

In reply to Re: problems redirecting STDOUT and STDERR to a $variable by kyle
in thread problems redirecting STDOUT and STDERR to a $variable by jeanluca

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