There's not two situations. The expression $a || $b evaluates to either $a's value if it has a not-false value (for the normal plethora of false values), othewise $b's value is used. What may happen in some cases is that expression's value is then used in a boolean context where it's further evaluated as true/false (e.g. if( $a || $b ) { ... }), but that's not really relevant in your example since print isn't going to impose a boolean context.

The cake is a lie.
The cake is a lie.
The cake is a lie.

In reply to Re: in search of disambiguation by Fletch
in thread in search of disambiguation by spx2

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