That code, while it found the main code error, will still sometimes show the error message.

$secretword=$words{$name}; if ($secretword eq ""){ $secretword="stupid"; }

If $name is not found in the hash %words, then $secretword will be undefined and will produce the error mentioned when used as if defined. If you however test for the definedness of $secretword you will be closer to the original aim.

if (defined $secretword) { $secretword = 'stupid'; }

In perl style I'd probably write:

$secretword = $words{$name} || 'stupid';

But that is a matter of choice.


In reply to Re: Re: HElp on program by repson
in thread HElp on program by alvarr3

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