Hello monks,

I can't understand the behavior of mkdir. When called mkdir(@a) it does not work. This seem to be different when using a scalar variable mkdir($a) or a constant argument mkdir('dir'). See the following session with the debugger: 

pp2@nereida:~/LGRID_Machine/examples$ perl -wde 0
main::(-e:1):   0
  DB<1> @a = ('/tmp/DIRECT', 18)

  DB<2> x @a
0  '/tmp/DIRECT'
1  18
  DB<3> x mkdir(@a) # seems ok
0  1
  DB<4> !!ls -ltr /tmp/DIRECT # ... but no:
ls: /tmp/DIRECT: No existe el fichero o el directorio
(Command exited 2)
  DB<5> x mkdir('/tmp/DIRECT', 18) # try without a var
0  1
  DB<6> !!ls -ltrd /tmp/DIRECT # now it works!
d--------- 2 pp2 pp2 4096 2008-03-04 11:43 /tmp/DIRECT
  DB<7> q

[download]

Many thanks

Casiano

In reply to mkdir with a list variable by casiano

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