if named subroutine declarations are evaluated bfore any invocations; then why are anonymous routine declarations not treated the same way? i tried something like a "forward declaration", where i hoped that the first declaration would reserve the name & data type in the symbol table and that the second definition would overwrite that entry in the symbol table. this failed. thanks

In reply to Re^2: nested routines, anonymous routines and location dependency by Anonymous Monk
in thread nested routines, anonymous routines and location dependency by Anonymous Monk

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