func(token5) is not returning 32. (32 & 32) is non-zero (32, to be exact) and a bitwise-or between a non-zero integer and any other integer can never be zero, regardless of the language you're using.

Either that, or C is processing the bitwise operators in a different order than you think it is, resulting in your parentheses being misplaced, although I can't readily think of any order in which (func(token5) & 32 | func(token5) & 128) could be handled that would produce zero when func(token5) returns 32.

In reply to Re: help porting a line of bitwise C code to perl by dsheroh
in thread help porting a line of bitwise C code to perl by blahblahblah

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