Here is some (admittedly, very inmature) Haskell to solve this problem.

type Data = (Int, Int, String)

bottom (b, _, _) = b
top    (_, t, _) = t
ide    (_, _, i) = i

contains :: Data -> Data -> Bool
x `contains` y = bottom x <= bottom y && top x >= top y

rangeSort1 :: [Data] -> [(Data, [Data])]
rangeSort1 r = map (\x -> (x, (filter (contains x) (filter (/=x) r))))
+  r

----

test :: [Data]
test = [ (11, 22, "A")
       , (22, 45, "B")
       , (22, 33, "C")
       , (25, 28, "D")
       , (47, 49, "E")
       ]
[download]

And here is the corresponding Perl, or at least, this is the closest I could get to this 'declarational' style in Perl:

sub bottom { shift->[0] };
sub top    { shift->[1] };
sub ide    { shift->[2] };

sub contains { bottom($_[0]) <= bottom($_[1]) && top($_[0]) >= top($_[
+1]) };

sub rangeSort1 { map { my $x = $_;
                       [$x, [grep {contains($x, $_)}
                                 (grep { ide($_) ne ide($x) } @_) ] ]
                   } @_ };

my $test = [ [11, 22, "A"]
           , [22, 45, "B"]
           , [22, 33, "C"]
           , [25, 28, "D"]
           , [47, 49, "E"]
       ];
[download]

If there's a Haskell/Perl guru out there with some free time, could you please improve on this?

Update: slightly improved Haskell:

rangeSort1 :: [Data] -> [(Data, [Data])]
rangeSort1 r = mapMaybe (\x -> let l = filter (contains x) . filter (/
+=x)
                               in case l r of
                                 []        -> Nothing
                                 otherwise -> Just (x, l r)
                        )  r
[download]

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