you are right to suspect that this would not work - the single \d as opposed to \d+ before the % would mean that the regex would fail to match unless the % was between 0 and 9.

what I expect you are looking for is for(<>) { /(\d+)%/; print if $1 >= 88 }

In reply to Re: Re: Regular Expression Question by larryk
in thread Regular Expression Question by Anonymous Monk

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