Am I missing something? (Maybe I am; I do have a cold today...)

How does the following line make sense? 

print qq|"one" != 0| unless "one" + 0 != 0; # prints: "one" != 0

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If ("one" + 0 != 0) then in my book ("one" != 0), right?

So you are printing that ("one" != 0) unless ("one" != 0)?

That's wrong. I think you actually proved that ("one" == 0) in both cases.

Update: Ah, he has seen the error of his ways already... He is now proving that ("one" == 0) and is yet non-NULL.

buckaduck

In reply to Re: in Perl 0 != 0 ... and this is good by buckaduck
in thread in Perl 0 != 0 ... and this is good by stefp

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