Funny, I started using '->' more as my Perl skills increased. Always seemed clearer to my eye.

But more to the point, this confuses me: 
my @x = (1,2,3);
my $x = ['x', 'y', 'z'];

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Pre-Perl 6 treats @x and $x as completely different variables. So I know that $x[1] is going to contain '2' and $x->[1] is going to contain 'y'. But according to the posts here, Perl 6 treats $x[1] as equivalent to $x->[1]. Just how is that supposed to work?

In reply to Re^2: [Perl 6] $ and @ - what is it coming to? by ruzam
in thread [Perl 6] $ and @ - what is it coming to? by John M. Dlugosz

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