use strict;
use warnings;

my $dir = shift @ARGV;         # Get first command line argument

opendir DIR, $dir or die $!;   # Open Directory

for my $file ( readdir(DIR) ){ # Loop through reading each file
    print "$file \n";
}

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Pancho

In reply to Re: Directory name as command line argument by Pancho
in thread Directory name as command line argument by max210

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