First what I've though was that the parens are causing the problem like in print:

$rh=1; $dist=1; print ($rh and $dist) ? 2 : -2

But quick check

#!perl sub aa { $rh=shift; $dist=shift; return ($rh and $dist) ? 2 : -2; } print aa;

has showed me I was wrong :) But I want to point at the issue - be very careful with paren at the beginning of parameters' list.


In reply to Re: faulty expression prob by grizzley
in thread faulty expression prob by perl-diddler

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