It's true that the following will result to $x getting assigned to either '1' or undefined:
$x = $y =~ /^(z*)/;
But I just got through looking at some code like this:
local($x) = $y =~ /^(z*)/;
which assigns $x to the value of z*.
Two questions: How does this work? I know local variables carry over between subroutines, but why is it affecting the behavior of this one line?
My second question is more of a Perl philosophy question. The above bit of code strikes me as a bit unorthodox. It seems that backreferences should be used since they were designed for this very kind of situation. Now, as a new Perl programmer, I know "there is more than one way to do it", but are there times one should strive for the more correct way of doing things?
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