I think adding use diagnositics; will help you understand this issue, and you can read more about the issue at http://www.perl.com/pub/a/2002/05/07/mod_perl.html:
(W) An inner (nested) named subroutine is referencing a lexical variable defined in an outer subroutine.

When the inner subroutine is called, it will probably see the value of the outer subroutine's variable as it was before and during the *first* call to the outer subroutine; in this case, after the first call to the outer subroutine is complete, the inner and outer subroutines will no longer share a common value for the variable. In other words, the variable will no longer be shared.

Furthermore, if the outer subroutine is anonymous and references a lexical variable outside itself, then the outer and inner subroutines will never share the given variable.

This problem can usually be solved by making the inner subroutine anonymous, using the sub {} syntax. When inner anonymous subs that reference variables in outer subroutines are called or referenced, they are automatically rebound to the current values of such variables.

In your case I think the problem is the definition of sub do_pkg_need_from_Dist. Does it really need to be defined as a closure within process_need_from_Dist?

Update: Your use of the variable $new_pkg is very odd: 

my $new_pkg;
{
   sub do_pkg_need_from_Dist {
      ...
      $new_pkg = ...; #  sets $new_pkg from the outer scope
      ...
      return $new_pkg;
   }

   $new_pkg = do_pkg_need_from_Dist(...); # sets $new_pkg again???
}

[download]
Declaring my $new_pkg; inside do_pkg_need_from_Dist should fix the error message about that variable.

In reply to Re: Perl scoping not logical...? by pc88mxer
in thread Perl scoping not logical...? by perl-diddler

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