I'm not quite sure I understand this perl behavior. 
my @bar=undef; 
print "def=",defined(@bar), " l=", $#bar, "\n";'

output:
def=1 l=0

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This is confusing me. I had a function that returned an array of answers if it found one or more answers, else it returned undef. On return, the result was assigned to an array and I tested the array for being defined or not.

I thought that if my function returned undef and that was assigned to an array, the array should also test as not defined. Buuuut....noooooOOOOoooo.... :-(

Why does my array, assigned "undef", then tell me it is defined? :-(... Very sad. I thought undef was the opposite of defined (sort of). I mean "undef" is a value (or an "unvalue"?), and defined is a test to see if a 'value' doesn't evaluate to 'undef', no? I'm sure there's a good reason for this, but at this point it sure doesn't seem "intuitive"...Arrg....

(this is what I get for doing whatever it is that I've done to deserve this! :-))....

In reply to undef==defined sometimes? by perl-diddler

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