If you want to access the removed part of the string, try:

$name =~ s/^(.*?)(\s*)$/$1/;

It is almost the same that you tried but with two little differences: the first quantifier is not greedy (*? instead of *) so it will not eat up the spaces and the second part of the expression now catches all \s characters until the end of line.

Rule One: Do not act incautiously when confronting a little bald wrinkly smiling man.

In reply to Re^2: Converting decimal value to hex by psini
in thread Converting decimal value to hex by coldmiser

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