A nit-pick, but the substitution should really be

s/.//s
to be equivalent with the others. Note the s modifier; it makes . match leading newlines as well. Otherwise you remove the first non-newline character from the string.
my %ex = ( "\n" . 'regexp' => sub { s/.// }, "\n" . 'regexp/s' => sub { s/.//s }, "\n" . 'chop' => sub { $_ = reverse; chop; $_ = reverse; }, "\n" . 'substr1' => sub { substr($_,0,1) = '' }, "\n" . 'substr2' => sub { $_ = substr($_,1) }, ); for (sort keys %ex) { $ex{$_}->(); print "[$_]\n"; } __END__ [chop] [ egexp] [regexp/s] [substr1] [substr2]

Update: Added example.

lodin


In reply to Re: Ways to delete start of string (The /s modifier) by lodin
in thread Ways to delete start of string by hsmyers

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