$ perl -MO=Deparse -e '@bar ||= (1,2,3)' Can't modify array dereference in logical or assignment (||=) at -e li +ne 1, at EOF -e had compilation errors. @bar ||= ('???', '???', 3); $ perl -MO=Deparse -we '@foo ||= 1' Can't modify array dereference in logical or assignment (||=) at -e li +ne 1, at EOF -e had compilation errors. BEGIN { $^W = 1; } @foo ||= 1;
So it seems that ||= generally isn't supported in perl.

Update: ok, other monks explained why. ||= returns a scalar.

A quick code search shows that all examples "out there" use it only in lines that are commented out, so it seems to be a common mistake actually


In reply to Re: ||= oddity by moritz
in thread ||= oddity by throop

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