I need a solution for this problem.
I have a text like this
Usage: perl [switches] [--] [programfile] [arguments]
-0[octal] specify record separator (\0, if no argument)
-a autosplit mode with -n or -p (splits $_ into @F)
-C[number/list] enables the listed Unicode features
-c check syntax only (runs BEGIN and CHECK blocks)
-d[:debugger] run program under debugger
I need the count of words in it, no 'wc -w' this time, because, wc -w will give me 45
I need the result 47 (which means I need to count only if a word character present in the word)
I have found an answer for this,
#!/usr/bin/perl -n
s/[^\w]+/ /g; # replace the non words with space
next if(/^\s*$/); # discard sentence with only spaces
$totalcount += (split(/ /) - 1); # split the sentence using space and
+count it
END{ print "Total: $totalcount<<\n"; }
is there any other answers
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