One more tidbit. The variable @foo is an array, but the expression @foo evaluates to a scalar or a list, depending on context. 
my $num_elemens = @foo;        # @foo evaluates to a scalar.
my ($first, $second) = @foo;   # @foo evaluates to a list.

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In reply to Re^4: Hash initialization works, but why? by ikegami
in thread Hash initialization works, but why? by throop

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