For one, whether you can open the file depends on what's in $bla. Second, what's that $path=s/\//\/; supposed to do? If it's meant to replace slashes with backslashes, it would at least have to be $path =~ s/\//\\/g;. But that seems inconsistent, as you're then using a slash yourself in "$path/$file"...

Also, given that you aren't really changing much in the path anyway, why not use the path $bla directly as is?

Could you describe in more detail what you're trying to achieve?

In reply to Re: Read file contents by almut
in thread Read file contents by Anonymous Monk

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