Pasting together the arguments is not going to work. Using $* only inserts one space between arguments. Just try this test program: 
#!/bin/bash
echo "$*"

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Invoking the script as: script-name a b  c          d yields: a b c d

From what you are saying, your program should only have one argument. You have to figure out why a shell is getting invoked.

In reply to Re^3: Perl equivelant to bash '$*' by pc88mxer
in thread Perl equivelant to bash '$*' by tillywern

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