Right; because a typeglob *is* an entry in the symbol table.> As you can see, $main::{$test2} evaluates to a typeglob.
Sorry, did I say that?> Saying that $main::{$test2} = > "test3" changes the scalar is technically incorrect.
In reply to RE: uSymbol Table Madness
by btrott
in thread question about variabies/references (ignore my previous botched entry)
by howard40
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