Please see Python code, then the Perl equivalent:
import re r = re.compile(r'(?P<A> a (?P<B> b))', re.X) m = r.search('ab') for k in m.groupdict(): print k, '=>', m.group(k) # 'A => ab' # 'B => b' print m.group('A') # 'ab' print m.group('B') # 'b'
Perl equivalent:
'ab' =~ /(?<A> a (?<B> b))/x; print "$_ => $+{$_}\n" for (keys(%+)); # 'A => ab' # ... nothing, thats it print "$+{'A'}\n"; # 'ab' print "$+{'B'}\n"; # 'b'
Perl doesn't enumerate all the keys if a named capture is nested within another. But it it clearly holds the correct value 'b' with the correct key 'B' in the hash. Is this a "feature" or a bug? ;)

In reply to Perl 5.10 Named Capture Bug? by delfarms

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