warning, non perl solution below!

Because youre using the expression "some DOS text" I will (possibly mistakenly) assume that you are using a *nix. In which case, you can use perl but its sort of overkill. I would use sed(1). 

[alex@creamy]$ sed 's:^L:\n:g' filename > filename.out

[download]
of course, to create a ^L you actually need to do a ^V^L or your shell will assume you really mean ^L. Also, \n is native to the gnu sed, and may not work in BSD or ATT *nix's.

brother dep.

--
Laziness, Impatience, Hubris, and Generosity.

In reply to Re: Replacing ^L with \n by deprecated
in thread Replacing ^L with \n by auzten

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