How about...

• @numbers = reverse sort @numbers
• $target = sum(@numbers)/2
• loop forever {
•   find largest $number in @numbers that is smaller than $target
•   exit loop if not found
•   add that number to @bucket
•   remove that number from @numbers
•   subtract that number from $target
• }
• return @bucket and @numbers

and in perl 5.10...

use List::Util qw(sum);
use List::MoreUtils qw(first_index);

#my @numbers = map { rand() * 100 } 1 .. 5;
my @numbers = (8,14,32,29);

my @b = split_evenly( \@numbers );

say "First container:  sum(@{$b[0]}) = ", sum @{$b[0]};
say "Second container: sum(@{$b[1]}) = ", sum @{$b[1]};

sub split_evenly {
    my @numbers = reverse sort { $a <=> $b } @{+shift};
    my $target = sum(@numbers) / 2;
    say "Target is $target";

    my @b;
    while ( 1 ) {
        my $index = first_index { $_ <= $target } @numbers;
        last if $index < 0;
        $target -= $numbers[$index];
        push @b, splice @numbers, $index, 1;
    }
    return \@b, \@numbers;
}
[download]

replace the says with print for perl < 5.10.

Tested, but not exhaustively. Use at your own risk. etc.

Update: changed the output so the lists are displayed.

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