But to find out if your solution is the best partition (and it's value is not sum/2) you have to check if there is a possible better partition, which means checking if the partition with the value sum/2 exists. Thus you have to solve the partition problem. D'oh.

In reply to Re^3: Divide array of integers into most similar value halves by moritz
in thread Divide array of integers into most similar value halves by Pepe

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