I read about it, but the Partition Problem just tells you if the list of numbers can be partitioned into 2 halves that have the same sum. I'm not really interested into checking that. I don't mind them having the same or different sum. I only want the best possible partition. Thanks anyway.
Note that the problem you are describing is (at best) just as hard as the original. Namely, if you can solve your problem, then you can solve the problem of finding a partition into equal halves by finding the best partition, and noting whether the difference in sums is 0.

UPDATE: Oops, sorry, both moritz and jethro pointed that out already.

In reply to Re^3: Divide array of integers into most similar value halves by JadeNB
in thread Divide array of integers into most similar value halves by Pepe

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